Question

se x (1 - x ) =1/4 então:

Answer 1

$x(1-x)= \frac{1}{4} \\ \\ x-x^2= \frac{1}{4} \\ \\ -x^2+x- \frac{1}{4} =0 \\ \\ -4x^2+4x-1=0$

Aplicando a fórmula de Bhaskara anexa

$delta = 16-4.(-4).(-1)=16-16=0 \\ \\ \sqrt{delta} =0 \\ \\ x_{1} 0 x_{2} = \frac{-4}{-8} = \frac{1}{2}$

s={$\frac{1}{2}$}