• Matéria: Matemática
  • Autor: viniciuscastro00000
  • Perguntado 9 anos atrás

a derivada da cadeia da função f(x)=(2x-1/3x²+x-2)³

Respostas

respondido por: josefarley
0
f(x)=1/27x^6+2/3x^5-28/9x^4+40/3x^3-76/3x^2+24x-8

respondido por: Anônimo
0
(2x- \frac{1}{3} x^2+x-2)^3 = \\  \\ =3  (2x-  \frac{x}{3} ^{2}+x-2 )^{3-1}. (2x- \frac{ x^{2} }{3} +x-2)'= \\  \\ 3  (2x-  \frac{x}{3} ^{2}+x-2 )^{2}. (2- \frac{2x}{3} +1)= \\  \\ 3(- \frac{ x^{2} }{3} +3x-2)^2.( \frac{6-2x+3}{3})= \\  \\ =3(- \frac{ x^{2} }{3} +3x-2)^2.( \frac{9-2x}{3})= \\  \\ = 3(- \frac{ x^{2} }{3} +3x-2)^2.( 3- \frac{2x}{3} )=3(3- \frac{2x}{3} )( -\frac{ x^{2} }{3} +3x-2)^2= \\  \\= (9-2x).(- \frac{ x^{2} }{3} +3x-2)^2
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