Question

a)1 log3 x

b) 0 = log2 x

c) log2 x= log2 5

d) log 2x = log6

Answer 1

a)
sabendo que 
$log_a(a) = 1$

então
$1=log_3(x)\\\\x=3$
:::::::::::::::::::::::::::::::::::::::::::
como
$log_a(1)=0$

$0=log_2(x)\\\\x=1$

::::::::::::::::::::::::::::::::::::::::::
lembrando que 
$log_a(b)=log_a(c)\\\\ b=c$

então
$log_2(x)=log_2(5)\\\\x=5$
:::::::::::::::::::::::::::::::::::::::::::::::::