Question

me ajudem,

a)
$\sqrt[3]{27} + \sqrt[4]{16} = \\ \sqrt[3]{125} - \sqrt[3]{8} = \\ \sqrt[2]{7} + \sqrt[3]{7} = \\ \sqrt[4]{5} + 2 {}^{4} \sqrt{5} = \\ \sqrt[3]{20} \div \sqrt[3]{2} = \\ \sqrt[4]{6} \div \sqrt[4]{2} = \\ \sqrt[5]{8} \div \sqrt[5]{4} = \\ \sqrt[4]{15} \div \sqrt[4]{5} = \\ \sqrt{40} \div \sqrt{8} =$
​

Answer 1

Explicação passo-a-passo:

$\sqrt[3]{27} +\sqrt[4]{16} =\\ \sqrt[3]{3^3} +\sqrt[4]{2^4} =\\ 3+2=5\\ --------------\\ \sqrt[3]{125} -\sqrt[3]{8} =\\ \sqrt[3]{5^3} -\sqrt[3]{2^3} =\\ 5-2=3\\ -----------------------\\ \sqrt[2]{7} +\sqrt[3]{7} =???\\ ---------\\ \sqrt[4]{5} +2\sqrt[4]{5} =\\ 3\sqrt[4]{5} \\ -----------------\\ \sqrt[3]{20} \div\sqrt[3]{2} =\\ \sqrt[3]{20\div2} =\\ \sqrt[3]{10}$

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$\sqrt[4]{6} \div\sqrt[4]{2} =\\ \sqrt[4]{6\div2} =\\ \sqrt[4]{3} \\ -----------------\\ \sqrt[5]{8} \div\sqrt[5]{4} =\\ \sqrt[5]{8\div4} =\\ \sqrt[5]{2} \\ ----------------\\ \sqrt[4]{15} \div\sqrt[4]{5} =\\ \sqrt[4]{15\div5} =\\ \sqrt[4]{3} \\ ------------\\ \sqrt{40} \div\sqrt{8} =\\ \sqrt{40\div8} =\\ \sqrt{5}$