Question

Resolva as questões:

a) 3a - 2a/3

b) 2x (ao quadrado)/3 - 1x (ao quadrado)/2

c) 1y/2 - 2y/5

d) 2x + 1x/2 - 3x/4​

Answer 1

a)

$\mathsf{3a-\dfrac{2a}{3}=\dfrac{9a-2a}{3}=\dfrac{7a}{3}}$

b)

$\mathsf{\dfrac{2{x}^{2}}{3}-\dfrac{1{x}^{2}}{2}=\dfrac{4{x}^{2}-3{x}^{2}}{6}=\dfrac{1{x}^{2}}{6}}$

c)

$\mathsf{\dfrac{y}{2}-\dfrac{2y}{5}=\dfrac{5y-4y}{10}=\dfrac{1y}{10}}$

d)

$\mathsf{2x+\dfrac{x}{2}-\dfrac{3x}{4}=\dfrac{8x+2x-3x}{4}=\dfrac{7x}{4}}$

Answer 2

Explicação passo-a-passo:

a)

$\sf 3a-\dfrac{2a}{3}=\dfrac{9a-2a}{3}=\red{\dfrac{7a}{3}}$

b)

$\sf \dfrac{2x^2}{3}-\dfrac{x^2}{2}=\dfrac{4x^2-3x^2}{6}=\red{\dfrac{x^2}{6}}$

c)

$\sf \dfrac{y}{2}-\dfrac{2y}{5}=\dfrac{5y-4y}{10}=\red{\dfrac{y}{10}}$

d)

$\sf 2x+\dfrac{x}{2}-\dfrac{3x}{4}=\dfrac{8x+2x-3x}{4}=\red{\dfrac{7x}{4}}$