Question

Determine os vértices da parábola que representa a função quadrática:A)y=x²-11x+30 B) y= x²+4x-12 C) y=x²-15x+56

Answer 1

a) x^2-11x+30=0
delta=b^2-4ac
delta=(-11)^2-4.1.30
delta=121-120
delta=1
xv=-b/2a
xv=-(-11)/2.1
xv=11/2
xv=5,5
yv=-delta/4a
yv=-1/4.1
yv=-1/4
yv=-0,25
(5,5 -0,25)
b) x^2+4x-12=0
delta=b^2-4ac
delta=4^2-4.1.(-12)
delta=16+48
delta=64
xv=-b/2a
xv=-4/2.1
xv=-4/2
xv=-2
yv=-delta/4a
yv=-64/4.1
yv=-64/4
yv=-16
(-2, -16)
c) x^2-15x+56=0
delta=b^2-4ac
delta=(-15)^2-4.1.56
delta=225-224
delta=1
xv=-b/2a
xv=-(-15)/2.1
xv=15/2
xv=7,5
yv=-delta/4a
yv=-1/4.1
yv=-1/4
yv=-0,25
(7,5. -0,25)

Answer 2

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