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(2/3x² - 3/5x +3) (x-1/2) =![(\frac{2x^2}{3}-\frac{3x}{5})(x-\frac{1}{2})=\frac{1}{30} x [4 x (5 x-7)+9]= \\
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\boxed{\frac{2 x^3}{3}-\frac{14 x^2}{15}+\frac{3 x}{10}}](https://tex.z-dn.net/?f=%28%5Cfrac%7B2x%5E2%7D%7B3%7D-%5Cfrac%7B3x%7D%7B5%7D%29%28x-%5Cfrac%7B1%7D%7B2%7D%29%3D%5Cfrac%7B1%7D%7B30%7D+x+%5B4+x+%285+x-7%29%2B9%5D%3D+%5C%5C%0A%5C%5C%0A%5Cboxed%7B%5Cfrac%7B2+x%5E3%7D%7B3%7D-%5Cfrac%7B14+x%5E2%7D%7B15%7D%2B%5Cfrac%7B3+x%7D%7B10%7D%7D "(\frac{2x^2}{3}-\frac{3x}{5})(x-\frac{1}{2})=\frac{1}{30} x [4 x (5 x-7)+9]= \\
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\boxed{\frac{2 x^3}{3}-\frac{14 x^2}{15}+\frac{3 x}{10}}")
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