Question

ME AJUDEM NESSA EQUAÇÃO
(x-1).(x-2)= (x-1).(2x + 3)

Answer 1

(x-1).(x-2)= (x-1).(2x + 3)
x²-2x-1x+2 = 2x² + 3x- 2x - 3
x² + 4x  =5
x² + 4x - 5= 0
Tirando baskhara, temos:
$\frac{-4 +- \sqrt{4^{2} - 4 . 1 . (-5)}}{2 . 1} = \frac{-4 +- \sqrt{16+20}}{2} = \frac{-4 +- \sqrt{36}}{2} = \frac{-4 +- 6}{2} = x' = \frac{-4+6}{2} = 1$
$x" = \frac{-4-6}{2} = -5$

Portanto, temos x'=1 e x"=-5