Question

me ajudem pfvr... preciso entregar antes do dia 20​

Answer 1

Resposta: (como as frações ficaram pequenas vou colocar elas na frente para você ver melhor)

a) $(\sqrt[3]{5} )^{2} = \sqrt[\frac{3}{2} ]{5}$    ===>  $\frac{3}{2}$

b) $(\sqrt[7]{a} )^{5} = \sqrt[\frac{7}{5}]{a}$   ===>  $\frac{7}{5}$

c) $(\sqrt[5]{2} )^{2} = \sqrt[\frac{5}{2}]{2}$   ===>  $\frac{5}{2}$

d) $(\sqrt[]{a} )^{3} = \sqrt[\frac{2}{3}]{a}$   ===>   $\frac{2}{3}$

e) $(\sqrt[]{a} )^{5} = \sqrt[\frac{2}{5}]{a}$   ===>  $\frac{2}{5}$

f) $(\sqrt[]{m} )^{10} = \sqrt[\frac{2}{10}]{m} = \sqrt[\frac{1}{5}]{m}$   ===>  $\frac{1}{5}$

g) $(\sqrt[]{a} )^{2} = \sqrt[\frac{2}{2}]{a} = a$

h) $(\sqrt[]{3a} )^{2} = \sqrt[\frac{2}{2}]{3a} = 3a$

i) $(\sqrt[3]{5b} )^{3} = \sqrt[\frac{3}{3}]{5b} = 5b$  

j) $(\sqrt[]{m^{3} } )^{8} = \sqrt[\frac{2}{8}]{m^{3} } = \sqrt[\frac{1}{4}]{m^{3} }$   ===>  $\frac{1}{4}$

l) $(\sqrt[]{2^{6} } )^{3} = \sqrt[\frac{2}{3}]{2^{6} }$   ===>  $\frac{2}{3}$

m) $(\sqrt[]{x} )^{7} = \sqrt[\frac{2}{7}]{x}$   ===>  $\frac{2}{7}$

n) $(\sqrt[]{4x^{3} } )^{2} = \sqrt[\frac{2}{2}]{4x^{3} } = 4x^{3}$

o) $5(\sqrt[]{2} )^{2} = 5\sqrt[\frac{2}{2}]{2} = 5*2 = 10$

p) $3a(\sqrt[]{5} )^{2} = 3a\sqrt[\frac{2}{2}]5} = 3a*5 = 15a$

q) $a(\sqrt[]{2} )^{4} = a\sqrt[\frac{2}{4}]{2} = a\sqrt[\frac{1}{2}]{2}$   ===>  $\frac{1}{2}$

r) $x(\sqrt[]{3} )^{4} = x\sqrt[\frac{2}{4}]{3} = x\sqrt[\frac{1}{2}]{3}$   ===>   $\frac{1}{2}$

s) $2a(\sqrt[]{ab} )^{2} = 2a\sqrt[\frac{2}{2}]{ab} = 2a*ab = 2a^{2} b$