Question

1. Determine
a) tg 900
b) tg (-540).
c) tg 1500°
d) tg 13 π
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Answer 1

a) tg (900°)

900° = 5π = π + 2 * (2π)

tg (900°) = tg (π) = tg (180°)

tg π = 0

b) tg (-540°)

-540° = -3π = -π -1 *2π

tg (-π) = tg (π)

tg π = 0

c) tg 1500°

1500° = 8π + 60° = π/3 + 4 * 2π

tg π/3 = tg 60° = √3

tg π/3 = √3

d) tg 13π

13 π = π + 6 * 2π

tg 13π = tg π

tg π = 0

Answer 2

Resposta:

b) tg (-540).

c) tg 1500°

d) tg 13 π

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