Question

Equação do segundo grau: x^2+5x+6=0?​

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+5x+6=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=5~e~c=6\\\\\Delta=(b)^{2}-4(a)(c)=(5)^{2}-4(1)(6)=25-(24)=1\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(5)-\sqrt{1}}{2(1)}=\frac{-5-1}{2}=\frac{-6}{2}=-3\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(5)+\sqrt{1}}{2(1)}=\frac{-5+1}{2}=\frac{-4}{2}=-2\\\\S=\{-3,~-2\}$

Answer 2

Resposta:

Explicação passo-a-passo:

a= 1 b=5 c=6

delta= 5^2-4*1*6

delta= 1

x= (-5 +- raiz (1) )/ 2*1

x=( -5 +- 1 )/2

x1= -5+1 / 2

x1 = -2

x2= -5-1/2

x2= -3

Respotas = (-2-3)