Question

y ao quadrado menos 8y mais 16 igual a zero

Answer 1

y^2-8y+16=0
delta=b^2-4ac
delta=(-8)^2-4.1.16
delta=64-64
delta=0
y=-b-/+ raiz de delta/2a
y=-(-8)-0/2.1
y=8-0/2
y=8/2
y=4

Answer 2

y² - 8y + 16 = 0
Δ = (-8) - 4 * 1 * 16
Δ = 64 - 64
Δ = 0

x' = b - √Δ / 2
x' = -8 / 2
x' = -4

x" = -8 / 2
x" = -4

y² - 8y + 16 = 0
(-4)² - 8 * (-4) + 16 
16 - 32 + 16
-16 + 16 = 0