Question

calcule o ponto médio dos segmentos.
A(-4,-2) B(-2,-4)

Answer 1

$A(-4,-2)\ ;\ B(-2,-4)\\\\\\x_M= \frac{x'+x''}{2} \to x_M= \frac{-4+(-2)}{2} \to x_M= \frac{-4-2}{2} \to x_M= \frac{-6}{2} \to x_M=-3\\\\\\ y_M= \frac{y'+y''}{2} \to y_M= \frac{-2+(-4)}{2} \to y_M= \frac{-2-4}{2} \to y_M= \frac{-6}{2} \to y_M=-3\\\\\\ P_M=\{-3;-3\}$