Como resolvo essa equação exponencial?
Anexos:
Niiya:
Cadê a igualdade?
Como assim?
Uma equação é uma igualdade
Só quer que simplifique a expressão?
Uma equação é uma igualdade com variável*
então não tem como resolver sem a igualdade?
De qualquer forma, obrigada, se conseguir ficarei grata.
Pronto
Respostas
respondido por:
1
Lembre-se: ![\sqrt{a}=\sqrt[2]{a}](https://tex.z-dn.net/?f=%5Csqrt%7Ba%7D%3D%5Csqrt%5B2%5D%7Ba%7D "\sqrt{a}=\sqrt[2]{a}")
Propriedades usadas:
![\dfrac{a^{x}}{a^{y}}=a^{x-y}\\\\\\\sqrt[Y]{a^{X}}=a^{X/Y}](https://tex.z-dn.net/?f=%5Cdfrac%7Ba%5E%7Bx%7D%7D%7Ba%5E%7By%7D%7D%3Da%5E%7Bx-y%7D%5C%5C%5C%5C%5C%5C%5Csqrt%5BY%5D%7Ba%5E%7BX%7D%7D%3Da%5E%7BX%2FY%7D "\dfrac{a^{x}}{a^{y}}=a^{x-y}\\\\\\\sqrt[Y]{a^{X}}=a^{X/Y}")
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![\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[2]{\dfrac{x^{1}}{x^{(4/5)}}}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[2]{x^{1-(4/5)}}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[2]{x^{(5-4)/5}}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[2]{x^{(1/5)}}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=x^{(1/5)/2}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=x^{1/10}\\\\\\\boxed{\boxed{\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[10]{x}}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cdfrac%7Bx%7D%7B%5Csqrt%5B5%5D%7Bx%5E%7B4%7D%7D%7D%7D%3D%5Csqrt%5B2%5D%7B%5Cdfrac%7Bx%5E%7B1%7D%7D%7Bx%5E%7B%284%2F5%29%7D%7D%7D%5C%5C%5C%5C%5C%5C%5Csqrt%7B%5Cdfrac%7Bx%7D%7B%5Csqrt%5B5%5D%7Bx%5E%7B4%7D%7D%7D%7D%3D%5Csqrt%5B2%5D%7Bx%5E%7B1-%284%2F5%29%7D%7D%5C%5C%5C%5C%5C%5C%5Csqrt%7B%5Cdfrac%7Bx%7D%7B%5Csqrt%5B5%5D%7Bx%5E%7B4%7D%7D%7D%7D%3D%5Csqrt%5B2%5D%7Bx%5E%7B%285-4%29%2F5%7D%7D%5C%5C%5C%5C%5C%5C%5Csqrt%7B%5Cdfrac%7Bx%7D%7B%5Csqrt%5B5%5D%7Bx%5E%7B4%7D%7D%7D%7D%3D%5Csqrt%5B2%5D%7Bx%5E%7B%281%2F5%29%7D%7D%5C%5C%5C%5C%5C%5C%5Csqrt%7B%5Cdfrac%7Bx%7D%7B%5Csqrt%5B5%5D%7Bx%5E%7B4%7D%7D%7D%7D%3Dx%5E%7B%281%2F5%29%2F2%7D%5C%5C%5C%5C%5C%5C%5Csqrt%7B%5Cdfrac%7Bx%7D%7B%5Csqrt%5B5%5D%7Bx%5E%7B4%7D%7D%7D%7D%3Dx%5E%7B1%2F10%7D%5C%5C%5C%5C%5C%5C%5Cboxed%7B%5Cboxed%7B%5Csqrt%7B%5Cdfrac%7Bx%7D%7B%5Csqrt%5B5%5D%7Bx%5E%7B4%7D%7D%7D%7D%3D%5Csqrt%5B10%5D%7Bx%7D%7D%7D "\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[2]{\dfrac{x^{1}}{x^{(4/5)}}}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[2]{x^{1-(4/5)}}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[2]{x^{(5-4)/5}}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[2]{x^{(1/5)}}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=x^{(1/5)/2}\\\\\\\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=x^{1/10}\\\\\\\boxed{\boxed{\sqrt{\dfrac{x}{\sqrt[5]{x^{4}}}}=\sqrt[10]{x}}}")
Propriedades usadas:
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