Question

Determine as raizes das equações:
b) Y+4(y - 1)=9 - 2(y+3)

C) 4(y - 2) +3 (2y - 1) = 6 (2y - 3)

Answer 1

Y+4(y - 1)=9 - 2(y+3)
y + 4y - 4 = 9 - 2y - 6
7y = 7
y = 1

4(y - 2) +3 (2y - 1) = 6 (2y - 3)
4y - 8 + 6y - 3 = 12y - 18
-2y =  -10 + 3
y = 7/2

Answer 2

b) Y+4(y - 1)=9 - 2(y+3)
y +4y -4 = 9 -2y -6
y +4y +2y = 9 +4 -6
7y = 13 -6
7y = 7
y= 7/7
y = 1

S{1}

C) 4(y - 2) +3 (2y - 1) = 6 (2y - 3)
4y -8 +6y -3 = 12y -18
4y +6y -12y = -18 +8 +3
10y -12y = -18 +11
-2y = -7.(-1)
2y = 7
y = 7/2   ou 3,5

S{7/2  ou  3,5}