Question

Alguém me ajuda a resolver, com conta montada

Answer 1

Resposta:

180=πrad

50= x

180x=50πrad

x=50πrad/180

x=5πrad/18

b)180=πrad

20=x

x=20πrad/180

x=πrad/9

c)180=πrad

10=x

x=10πrad/180

x=πrad/18

d)180=πrad

25=x

x=5πrad/36

e)

180=πrad

5=x

x=πrad/36

f)180=πrad

15=x

x=15πrad/180

x=πrad/12

g)

180=πrad

30=x

x=30πrad/180

x=πrad/6

h) 180=πrad

60=x

x=60πrad/180

x=πrad/3

i)180=πrad

105=x

105πrad=180x

x=105πrad/180

x=7ππrad/12

j)

180=πrad

100=x

x=100πrad/180

x=5πrad/9

2)

180=π

x= 4π/3

πx=720π/3

x=720/3

x=240

180=π

x= 7/6πrad

πx=1260/6πrad

x=210

180=π

x=3/9πrad

x=60

Explicação passo-a-passo:

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