Question

Matemática
√36 + 2 =

√25 + 2 • √16 + 6=

√81 -3 • √9 + √1=

7 • √81v- 2 • √49 + 2=

(√4 + √16)² -(√1)=

(√144 - √121)² -(√1)=

2√2 - √8=

√3 + 2√27 + √243=

√2 • √7=

​

Answer 1

$\mathsf{\sqrt{36}+2=6+2=8}$

$\mathsf{\sqrt{25}+2.\sqrt{16}+6=5+2.4+6}\\\mathsf{5+8+6=19}$

$\mathsf{\sqrt{81}-3.\sqrt{9}+\sqrt{1}=9-3.3+1}\\\mathsf{9-9+1=1}$

$\mathsf{7.\sqrt{81}-2.\sqrt{49}+2=7.9-2.7+2}\\\mathsf{63-14+2=51}$

$\mathsf{{(\sqrt{4}+\sqrt{16})}^{2}-(\sqrt{1})={(2+4)}^{2}-1}\\\mathsf{{6}^{2}-1=36-1=35}$

$\mathsf{{(\sqrt{144}-\sqrt{121})}^{2}-(\sqrt{1})}\\\mathsf{{(12-11)}^{2}-1=1-1=0}$

$\mathsf{2\sqrt{2}-\sqrt{8}=2\sqrt{2}-2\sqrt{2}=0}$

$\mathsf{\sqrt{3}+2\sqrt{27}+\sqrt{243}}\\\mathsf{\sqrt{3}+2.3\sqrt{3}+9\sqrt{3}=\sqrt{3}+6\sqrt{3}+9\sqrt{3}=16\sqrt{3}}$

$\mathsf{\sqrt{2}.\sqrt{7}=\sqrt{14}}$

Answer 2

Olá espero servir pra algo (๑╹◡╹๑)ﾉ

Na figura, temos os números primos.

Exemplos:

a) 28/2 = 14 → 14/2 = 7 → 7/7 = 1

28 = 2.2.7 = 2².7

b) 30/2 = 15 → 15/3 = 5 → 5/5 = 1

30 = 2.3.5

c) 32/2 = 16 → 16/2 = 8 → 8/2 = 4 → 4/2 = 2 → 2/2 = 1

32 = 2.2.2.2.2 = 2⁵