Question

simplifique as equaçao a) √396-√108+√176+√675

Answer 1

Resolvendo separadamente:
$\sqrt{396}= \sqrt{2^2.3^2.11}=2.3 \sqrt{11}=6 \sqrt{11}$

$\sqrt{108} = \sqrt{2^2.3^3}=2.3 \sqrt{3}=6 \sqrt{3}$

$\sqrt{176}= \sqrt{2^4.11}=2^2 \sqrt{11}=4 \sqrt{11}$

$\sqrt{675}= \sqrt{3^3.5^2}=3.5 \sqrt{3}=15 \sqrt{3}$

Então , fica assim:
$6 \sqrt{11}-6 \sqrt{3}+4 \sqrt{11} +15 \sqrt{3}=$

$6 \sqrt{11}+4 \sqrt{11}+15 \sqrt{3}-6 \sqrt{3} =$

$10 \sqrt{11}+9 \sqrt{3}$