Question

3x^2+x-2=0
por favor respondammm

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~3x^{2}+x-2=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=3{;}~b=1~e~c=-2\\\\\Delta=(b)^{2}-4(a)(c)=(1)^{2}-4(3)(-2)=1-(-24)=25\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(1)-\sqrt{25}}{2(3)}=\frac{-1-5}{6}=\frac{-6}{6}=-1\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(1)+\sqrt{25}}{2(3)}=\frac{-1+5}{6}=\frac{4\div2}{6\div2}=\frac{2}{3} \\\\\\S=\{-1,~\frac{2}{3}\}$