• Matéria: Matemática
  • Autor: janainacamposs
  • Perguntado 6 anos atrás

(4-3+2).(-2+1+3).2-{(-5-1+4).3-[-2+(-2)]}=​

Respostas

respondido por: 4288
1

Espero ter ajudado.

\left(4-3+2\right)\left(-2+1+3\right)\cdot \:2-\left\{\left(-5-1+4\right)\cdot \:3-\left[-2+\left(-2\right)\right]\right\}\\\\3\left(-2+1+3\right)\cdot \:2-\left\{\left(-5-1+4\right)\cdot \:3-\left[-2+\left(-2\right)\right]\right\}\\\\3\cdot \:2\cdot \:2-\left\{\left(-5-1+4\right)\cdot \:3-\left[-2+\left(-2\right)\right]\right\}\\\\3\cdot \:2\cdot \:2-\left(-2\right)\\\\12-\left(-2\right)\\\\=14

respondido por: juniorideia
1

(4 - 3 + 2) * (-2 + 1 + 3) * 2 - {(-5 -1 + 4) * 3 - [-2 + (-2)]}

3 * 2 * 2 -  {-2 * 3 - [- 2 - 2]}

12 - {-6 - [-4]}

12 - {-6 + 4}

12 - {-2}

12 + 2

14

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