• Matéria: Matemática
  • Autor: emonilda22
  • Perguntado 9 anos atrás

resolvam pfvor pfvor!
x+8+2(5x-3) maior que 6+3x

Respostas

respondido por: LuanaSC8
0
x+8+2(5x-3)\ \textgreater \ 6+3x\to \\\\ x+8+10x\ \textgreater \ 6+3x\to \\\\x+10x-3x\ \textgreater \ 6-8+6\to \\\\ 8x\ \textgreater \ 4\to \\\\ x\ \textgreater \  \frac{4}{8} \to \\\\ x\ \textgreater \  \frac{1}{2} \\\\\\\\S=\{xER|~x\ \textgreater \  \frac{1}{2}\}
respondido por: Anônimo
0
x + 8 + 2.(5x - 3) > 6 + 3x
x + 8 + 10x - 6 > 6 + 3x
x + 10x + 8 - 6 > 6 + 3x
11x + 2 > 6 + 3x
11x - 3x > 6 - 2
8x > 4
x > 4  (:4)
      8   (:4)

x > 1
      2

{x ∈ R / x > 1/2}

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