Question

delta e báskara de 3x (ao quadrado) -4x+1=0

Answer 1

Δ :
 $b^2 - 4.a.c\\ (-4)^2 - 4.3.1\\16-12=4$
Δ = 4
$x= \frac{- b + ou - \sqrt{delta} }{2.a}\\x=\frac{ -(-4) + ou - \sqrt{4} }{2.3}\\x=\frac{4+ou- 2}{6}\\x'=\frac{4+2}{6}=\frac{6}{6}=1\\x'=1\\ x" = \frac{4-2}{6}\\x" = \frac{2}{6}=\frac{1}{3}\\x" = \frac{1}{3}$