Question

Determine o valor de



e marque a opção correta.

Escolha uma:
a. 3/5
b. - 4/5
c. - 3/4
d. 0
e. -2

Answer 1

$\mathsf{x^2+6x+5=(x+1)(x+5)}\\\mathsf{x^2-3x-4=(x+1)(x-4)}$

$\displaystyle\mathsf{\lim_{x \to 1}\dfrac{x^2+6x+5}{x^2-3x-4}}\\\displaystyle\mathsf{\lim_{x \to 1}\dfrac{(x+1)(x+5)}{(x+1)(x-4)}}$

$\displaystyle\mathsf{\lim_{x \to 1}\dfrac{(x+5)}{(x-4)}=\dfrac{1+5}{1-4}=\dfrac{6}{-3}=-2}$

$\large\boxed{\boxed{\boxed{\mathsf{\maltese~~Alternativa~e}}}}$