Question

efectua e simplifique os termos semelhantes:

(3a-2) x (-a+5) =


(x-1/2) (2x+6) =


(b-3) (b/3 - 1/6) =



(x^2 - 2x +1/4) (x/2-1) =


(2x+1)^2 =


me ajudem se for possível pfv​

Answer 1

Resposta:

a) $-3a^2+15a+2a-10 = 3a^2+17a-10=(3a+17)a-10$

b) $2x^2-6x-\frac{2x}{2}-\frac{6}{2}= 2x^2+5x-3=(2x+5)x-3$

c)$\frac{b^2}{3} -\frac{b}{6} -\frac{3b}{3} +\frac{3}{6} = \frac{b^2}{3} -\frac{b}{6} -b+\frac{1}{2}= (\frac{b}{3} -\frac{1}{6} -1)b +\frac{1}{2}= = (\frac{b}{3} -\frac{7}{6})b +\frac{1}{2}$

d)

$\frac{x^3}{2} - x^2-\frac{2x^2}{2} +2x-\frac{x}{8} -\frac{1}{4} =\frac{x^3}{2} - x^2-x^2 +2x+\frac{x}{8} -\frac{1}{4}=\frac{x^3}{2} - 2x^2 +\frac{17x}{8} -\frac{1}{4}\\(\frac{x}{2} - 2)x^2+\frac{17x}{8} -\frac{1}{4}$

e)$4x^2+4x+1$