Question

quanto é (x+2) (x+3)

Answer 1

$(x+2) (x+3)\to \\\\x^2+3x+2x+6=0\to\\\\ x^2+5x+6=0\\\\ a=1; b=5;\ c=6\\\\\\ \Delta=b^2-4ac\to \Delta=5^2-4*1*6\to \Delta=25-24\to \Delta=1\\\\ x' \neq x''\\\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-5\pm \sqrt{1} }{2*1} \to x= \frac{-5\pm 1 }{2} \to \\\\\\ x'= \frac{-5+1 }{2} \to x'= \frac{-4 }{2} \to x'=-2\\\\\\ x''= \frac{-5-1 }{2} \to x''= \frac{-6 }{2} \to x''=-3\\\\\\\\ S=\{-3;-2\}$