Question

racionalização 7/√3-2​

Answer 1

$\frac{7}{\sqrt{3}-2 } =$

$\frac{7}{\sqrt{3}-2 } . \frac{\sqrt{3}+2 }{\sqrt{3}+2 } =$

$\frac{7\sqrt{3}+ 14 }{3-2\sqrt{3}+2\sqrt{3}-4 } =$

$\frac{7\sqrt{3}+14 }{-1} =$

$-7\sqrt{3} - 14$

Bons estudos!