Question

Gostaria de saber as seguintes questões:
a)710+(420\310)-72
b)Raiz quadrada de 12
c)E qual é a raiz quadrada de 789

Answer 1

   
     a)
                $710 +( \frac{420}{310} )-72 \\ \\ =710-72+ \frac{42}{31} \\ \\ =638- \frac{42}{31} \\ \\ = \frac{31x638-42}{31} \\ \\ = \frac{19778-42}{31} \\ \\ = \frac{19747}{31} \\ \\ =637$

    b)
                 $\sqrt{12} = \sqrt{4x3} =2 \sqrt{3}$
                           Se precisar valor numérico, use
                                       $\sqrt{3} =1,7321$
  
     c) 
               $\sqrt{789} =28,1$

Answer 2

$a)710+ \frac{42}{31} -72= \frac{22010+42-2232}{31} = \frac{19820}{31} ;$$b) \sqrt{12} = \sqrt{2 ^{2}.3 } =2 \sqrt{3} ;$ $c) \sqrt{789} = 28,1$