Question

alguem me ajuda em equaçao de segundo grau

1= x²+x-306=0
2= x²-5x-50=0
3= x²+35-200=0

Answer 1

a=1 b=1 c= -306

D= b^2 - 4*a*c
D= 1^2 - 4*1*(-306)
D= 1+1224
D=1225

X= - b +- raiz de D/2*a
X ' = - 1 + raiz 1225/2*1
X ' = -1 + 35/2
X' = 34/2 = 17

X" = -1-35/2
X " = 36/2 = -18

Answer 2

>>Questão 1:
x²+x-306=0
$\frac{-1+- \sqrt{1-4*1*-306} }{2*1} = \frac{-1+- \sqrt{1225} }{2} = \frac{-1+-35}{2}$

Assim, 
$x1= \frac{-1+35}{2} = \frac{34}{2} = 17$

$x2= \frac{-1-35}{2} = \frac{-36}{2} = -18$

>> Questão 2:
x²-5x-50=0 
$\frac{5+- \sqrt{25-4*1*-50} }{2*1} = \frac{5+- \sqrt{225} }{2} = \frac{5+-15}{2}$

Assim,
$x1= \frac{5+15}{2} = \frac{20}{2} = 10$

$x2= \frac{5-15}{2} = \frac{-10}{2} = -5$

>> Questão 3:
x²+35-200=0 
$\frac{-35+- \sqrt{1225-4*1*-200} }{2*1} = \frac{-35+- \sqrt{2025} }{2} = \frac{-35+-45}{2}$

Assim,
$x1= \frac{-35+45}{2} = \frac{10}{2} = 5$

$x2= \frac{-35-45}{2} = \frac{-80}{2} = -40$