Question

$( \sqrt[6]{2} elevado a x) = 0,5$

Answer 1

$\sqrt[6]{2^x} = 0,5 \\ \sqrt[6]{2^x} = \frac{1}{2} \\ 2^{ \frac{x}{6} } = 2^{-1} \\ \frac{x}{6} = -1 \\ x = -6$