Question

me aajudem com urgencia
n
Σ =1 (2j-1)=n²
j

Answer 1

$\displaystyle S=\sum\limits_{j=1}^n(2j-1)\\ \\ S=2\sum\limits_{j=1}^nj-\sum\limits_{j=1}^n1\\ \\ S=2\left[\frac{n(n+1)}{2}\right]-n\\ \\ S=n(n+1)-n\\ \\ S=n^2+n-n\\ \\ \boxed{S=n^2}$