Question

 

 

a)(x+2).(x-8)≤0

 

b) 2x²-4x+5>0

 

c)│5-2x│>3

Answer 1

 Shianver,

boa tarde!

 

a)

 

I:

 

$\\ x + 2 \leq 0 \\ \boxed{x \leq - 2}$

 

 

I:

 

$\\ x - 8 \leq 0 \\ \boxed{x \leq 8}$

 

 

 Estudando os sinais!

 

$\boxed{S = \left \{ x \in \mathbb{R} / x \leq - 2 \cup x \geq 8 \right \}}$