Question

(2x+3). (x-1)= 3 baskara​

Answer 1

Resposta:

Explicação passo-a-passo:

(2x+3). (x-1)= 3

2x²-2x+3x-3=3

2x²+x-3-3=0

2x²+x-6=0

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~2x^{2}+x-6=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=2{;}~b=1~e~c=-6\\\\\Delta=(b)^{2}-4(a)(c)=(1)^{2}-4(2)(-6)=1-(-48)=49\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(1)-\sqrt{49}}{2(2)}=\frac{-1-7}{4}=\frac{-8}{4}=-2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(1)+\sqrt{49}}{2(2)}=\frac{-1+7}{4}=\frac{6\div2}{4\div2}=\frac{3}{2}\\\\\\S=\{-2,~\frac{3}{2}\}$