Question

determine o valor numérico de x= -b+raiz quadrada de b2 - 4ac/2a sendo a = 1, b= 5 e c = 6

Answer 1

Oie, Td Bom?!

>>> Resolvendo a expressão.

x = -b+√{b²-4ac}/2a

>>> Substitua: a = 1, b = 5 e c = 6.

x = -5√{5²-4×1×6}/2×1

x = -5+√{25-24}/2

x = -5+√1/2

x = -5+1/2

x = -4/2

x = - 2

Att. Makaveli1996

Answer 2

Resposta:

$\mathsf{X=-2}$

Explicação passo-a-passo:

Expressão algébrica

$\mathsf{X=\frac{-B+\sqrt{{B}^{2}-4\times A\times C}}{2A}}$

$\mathsf{X=\frac{-5+\sqrt{{5}^{2}-4\times 1\times 6}}{2\times1}}$

$\mathsf{X=\frac{-5+\sqrt{25-24}}{2}}$

$\mathsf{X=\frac{-5+\sqrt{1}}{2}}$

$\mathsf{X=\frac{-5+1}{2}}$

$\mathsf{X=\frac{-4}{2}}$

$\mathsf{X=-2}$