Question

me ajuemmmmmmmmmmm CALCULE A MASSA MOLECULAR COM AS CONTAS PLS
MASSA MOLECULAR ME AJUDEM URGENTE
a)
CH3OH
b) H4P207
C) C12H22O11
D) HNO3

Answer 1

Explicação:

a) $\text{CH}_{3}\text{OH}$

$\text{MM}(\text{C})=12~\text{g}/\text{mol}$

$\text{MM}(\text{H})=1~\text{g}/\text{mol}$

$\text{MM}(\text{O})=16~\text{g}/\text{mol}$

Então:

$\text{MM}(\text{CH}_{3}\text{OH})=12+3\cdot1+16+1$

$\text{MM}(\text{CH}_{3}\text{OH})=12+3+17$

$\text{MM}(\text{CH}_{3}\text{OH})=32~\text{g}/\text{mol}$

b) $\text{H}_{4}\text{P}_{2}\text{O}_{7}$

$\text{MM}(\text{H})=1~\text{g}/\text{mol}$

$\text{MM}(\text{P})=31~\text{g}/\text{mol}$

$\text{MM}(\text{O})=16~\text{g}/\text{mol}$

Então:

$\text{MM}(\text{H}_{4}\text{P}_{2}\text{O}_{7})=4\cdot1+2\cdot31+7\cdot16$

$\text{MM}(\text{H}_{4}\text{P}_{2}\text{O}_{7})=4+62+112$

$\text{MM}(\text{H}_{4}\text{P}_{2}\text{O}_{7})=178~\text{g}/\text{mol}$

c) $\text{C}_{12}\text{H}_{22}\text{O}_{11}$

$\text{MM}(\text{C})=12~\text{g}/\text{mol}$

$\text{MM}(\text{H})=1~\text{g}/\text{mol}$

$\text{MM}(\text{O})=16~\text{g}/\text{mol}$

Então:

$\text{MM}(\text{C}_{12}\text{H}_{22}\text{O}_{11})=12\cdot12+22\cdot1+11\cdot16$

$\text{MM}(\text{C}_{12}\text{H}_{22}\text{O}_{11})=144+22+176$

$\text{MM}(\text{C}_{12}\text{H}_{22}\text{O}_{11})=342~\text{g}/\text{mol}$

d) $\text{HNO}_3$

$\text{MM}(\text{H})=1~\text{g}/\text{mol}$

$\text{MM}(\text{N})=14~\text{g}/\text{mol}$

$\text{MM}(\text{O})=16~\text{g}/\text{mol}$

Então:

$\text{MM}(\text{HNO}_3)=1+14+3\cdot16$

$\text{MM}(\text{HNO}_3)=15+48$

$\text{MM}(\text{HNO}_3)=63~\text{g}/\text{mol}$