Question

Resolva:

$A = \frac{4}{3} B = -2 Calcule: 2.A^-^2+B^-^4$

Answer 1

$2A^{-2}+B^{-4}\\ \\ 2.(\frac{4}{3})^{-2}+(-2)^{-4}=\\ \\ 2.(\frac{3}{4})^2+\frac{1}{(-2)^4}=\\ \\ 2.\frac{9}{16}+\frac{1}{16}=\\ \\ \frac{9}{8}+\frac{1}{16}=\frac{19}{16}$

Answer 2

$\[\\2.A^-2+B^-4 \\\\2.(\frac{4}{3})^{-2}+(-2)^{-4} \\\\2.\frac{9}{16}+\frac{1}{16} \\\\\boxed{\frac{9}{8}+\frac{1}{16}=\frac{19}{16}}\]$