Question

Ao racionalizar $\frac{18}{\sqrt{6} }$ e $\frac{5}{2\sqrt{3} }$ obtém-se, respectivamente..?

Answer 1

Explicação passo-a-passo:

$\bullet~~M=\dfrac{18}{\sqrt{6}}$

$M=\dfrac{18}{\sqrt{6}}\cdot\dfrac{\sqrt{6}}{\sqrt{6}}$

$M=\dfrac{18\sqrt{6}}{6}$

$M=3\sqrt{6}$

$\bullet~~N=\dfrac{5}{2\sqrt{3}}$

$N=\dfrac{5}{2\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}$

$N=\dfrac{5\sqrt{3}}{2\cdot3}$

$N=\dfrac{5\sqrt{3}}{6}$

Answer 2

Resposta:

Explicação passo-a-passo:

Racionalização de denominadores

$\frac{18}{\sqrt{6} } \times \frac{\sqrt{6} }{\sqrt{6} } =\frac{18 \sqrt{6} }{6} =>>3\sqrt{6} \\\\\frac{5}{2\sqrt{3} } \times \frac{\sqrt{3}}{\sqrt{3}} =\frac{5\sqrt{3}}{2\times3} =>>\frac{5\sqrt{3}}{6}$