Question

resolva no universo dos complexos, as equações incompletas do 2°grau x elevado ao quadrado + 24=0​

Answer 1

Vamos lembrar que  $i =\sqrt{-1}$ .

Agora resolvendo com bhaskhara:

$x^2 +24=0\\\\\Delta=b^2 -4ac\\\\\Delta = (0)^2 -4\times 1\times24\\\\\Delta =-96\\\\x = \dfrac{-b \pm \sqrt{\Delta}}{2a}\\\\x = \dfrac{\pm\sqrt{-96}}{2}\\\\x = \dfrac{\pm\sqrt{-1\times2^5\times3}}{2}\\\\x = \dfrac{\pm4 i\sqrt{6}}{2}\\\\x = \pm2i\sqrt{6}$