Question

utilizando a fatoraçao simplifique a fraçao algebrica
3x2-18x+27
3x2-9x

Answer 1

$\frac{3x^2-18x+27}{3x^2-9x} = \frac{3\cdot(x^2-6x+9)}{3x\cdot(x-3)} = \frac{3\cdot(x-3)\cdot(x-3)}{3x\cdot(x-3)} = \frac{x-3}{x}$

Answer 2

$\frac{3 x^{2} -18x+27}{3 x^{2} -9x} = \frac{3( x^{2}-6x+9) }{3( x^{2} -3x)} = \frac{ x^{2} -6x+9}{ x^{2} -3x} \\ \\ \frac{(x-3)(x-3)}{x(x-3)} = \frac{x-3}{x} = \frac{x(1- \frac{3}{x} )}{x} =1- \frac{3}{x}$