Question

Por favor alguem me ajude na equação : 6x²+5x+1=10 URGENTE !!!!

Answer 1

$6x^2+5x+1-10=0\\6x^2+5x-9=0\\\Delta=b^2-4ac=25-4.6(-9)=241\\x=\frac{-5\pm\sqrt{241}}{2.6}\\\boxed{x'=\frac{-5-\sqrt{241}}{12}}\\\boxed{x''=\frac{-5+\sqrt{241}}{12}}$

Answer 2

36x+5x+1=10
41x+1=10
41x=10-1
41x=9
x=41÷9
x=4,555...