• Matéria: Matemática
  • Autor: helenamathiasbonne
  • Perguntado 6 anos atrás

40 PONTOS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! raionalize os denominadores:a)\frac{10}{\sqrt{5} }; b)\frac{2\sqrt{2} }{\sqrt{3} }; c)\frac{9}{2\sqrt{3} }

Respostas

respondido por: Makaveli1996
0

Oie, Td Bom?!

a)

 =  \frac{10}{ \sqrt{5} }

 =  \frac{10}{ \sqrt{5} }  \times  \frac{ \sqrt{5} }{ \sqrt{5} }

 =  \frac{10 \sqrt{5} }{ \sqrt{5}  \sqrt{5} }

 =  \frac{10 \sqrt{5} }{5}

 = 2 \sqrt{5}

b)

 =  \frac{2 \sqrt{2} }{ \sqrt{3} }

 =  \frac{2 \sqrt{2} }{ \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }

 =  \frac{2 \sqrt{2} \sqrt{3}  }{ \sqrt{3} \sqrt{3}  }

 =  \frac{2 \sqrt{6} }{3}

c)

 =  \frac{9}{2 \sqrt{3} }

 =  \frac{9}{2 \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }

 =  \frac{9 \sqrt{3} }{2 \sqrt{3} \sqrt{3}  }

 =  \frac{9 \sqrt{3} }{2 \times 3}

 =  \frac{9 \sqrt{3} }{6}

 =  \frac{3 \sqrt{3} }{2}

Att. Makaveli1996

respondido por: Anônimo
0

Explicação passo-a-passo:

a)

\sf \dfrac{10}{\sqrt{5}}

\sf =\dfrac{10}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}

\sf =\dfrac{10\sqrt{5}}{5}

\sf =\red{2\sqrt{5}}

b)

\sf \dfrac{2\sqrt{2}}{\sqrt{3}}

\sf =\dfrac{2\sqrt{2}}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}

\sf =\red{\dfrac{2\sqrt{6}}{3}}

c)

\sf \dfrac{9}{2\sqrt{3}}

\sf =\dfrac{9}{2\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}

\sf =\dfrac{9\sqrt{3}}{2\cdot3}

\sf =\red{\dfrac{3\sqrt{3}}{2}}

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