Question

b) B=(bij) 2x3, tal que = i-j

Answer 1

(b11. b12. b13) (0. -1. -2)
(b21. b22. b23) (1. 0. -1)
bij=i-j
b11=1-1
b11=0
bij=i-j
b21=2-1
b21=1
bij=i-j
b12=1-2
b12=-1
bij=i-j
b22=2-2
b22=0
bij=i-j
b13=1-3
b13=-2
bij=i-j
b23=2-3
b23=-1