Question

7(2x–4)/5 – (4y–2)/(–3) < (5y+1)/7

Answer 1

$\frac{7(2y-4)}{5} + \frac{(4y-2)}{3} \ \textless \ \frac{5y+1}{7} --\ \textgreater \ \frac{294 y-588}{105} + \frac {140y-70}{105}\ \textless \ \frac{75y+15}{105} --\ \textgreater$$294 y+140y-75y \ \textless \ 588+70+15--\ \textgreater \ 359y \ \textless \ 673--\ \textgreater \ y \ \textless \ \frac{673}{359}$