Question

ajudemmmmm pfvrrrrrrrrrrrr​

Answer 1

Resposta:

1. x' = -2 ; x" = 3

Explicação passo-a-passo:

${2x}^{2} - 2x - 12 = 0 \\ \\ x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ a = 2 \\ b = - 2 \\ c = - 12 \\ \\ x = \frac{ - ( - 2) + - \sqrt{ {( - 2)}^{2} - 4 \times 2 \times ( - 12)} }{2 \times 2} \\ x = \frac{2 + - \sqrt{4 - 8 \times ( - 12)} }{4} \\ x = \frac{2 + - \sqrt{4 + 96} }{4} \\ x = \frac{2 + - \sqrt{100} }{4} \\ x = \frac{2 + - 10}{4} \\ \\ {x}^{1} = \frac{2 + 10}{4} = \frac{12}{4} = 3 \\ {x}^{2} = \frac{2 - 10}{4} = - \frac{8}{4} = - 2$