Question

Considere a função definida por f(x)=x^2-3x+1. A taxa média de variação no intervalo [0, 3] é:

Answer 1

A taxa media de variacao T da funcao f(x) no intervalo [a,b] eh dada pela formula:

$T=\dfrac{f(b)-f(a)}{b-a}$

Logo:

$a=0\\\\b=3\\\\f(a)=f(0)=(0)^2-3(0)+1=0-0+1=1\\\\f(b)=f(3)=(3)^2-3(3)+1=9-9+1=1\\\\\\T=\dfrac{f(b)-f(a)}{b-a}=\dfrac{1-1}{3-0}=\dfrac{0}{3}=\boxed{0}$