Question

a6 em cada PG (-7,-14,-28,....)
​

Answer 1

Explicação passo-a-passo:

A) (-7,14,-28,...)

b) (-48,-24,-12,...)

c) (64/25,8/5,1,...)

a) \\
a_6=a_1.q^5\\
\\
a_6=(-7).(-2)^5\\
\\
a_6=(-7).(-32)\\
\\
\boxed{a_6=224}

b) \\
a_6=a_1.q^5\\
\\
a_6=(-48).(\frac{1}{2})^5\\
\\
\boxed{a_6=(-48).\frac{1}{32}=-\frac{48}{32}=-\frac{3}{2}}

c)\\
a_6=a_1.q^5\\
\\
\boxed{a_6=(\frac{64}{25}).(\frac{5}{8})^5=(\frac{64}{25}).(\frac{3125}{32768})=\frac{125}{512}}