Question

sendo x=4,333... e y=3,444..., calcule o valor de:

1)9.x-18.y

 

2)x.y

 

3)x/y

 

4)y/x

 

5)x.y/x+y

 

6)x:y/x+y

 

7)x.y/x:y

 

 

valeu galera...é desespero mesmo...SerginhoHunter

Answer 1

Olá, Malu Black.

 

$<var>x=4,333...=4+\frac39=4+\frac13=\frac{12+1}</var><var>{3}=\frac{13}3\\\\y=3,444...=3+\frac49=\frac{27+4}9=\frac{31}9\\\\ 1)9x-18y=9\cdot \frac{13}3-18\cdot \frac{31}9=3\cdot 13-2\cdot 31=39-62=-23\\\\ 2)x.y=\frac{13}3\cdot \frac{31}9=\frac{403}{27}\\\\ 3)x/y=\frac{13}3\cdot \frac9{31}=\frac{39}{31}\\\\ 4)y/x=\frac{31}9 \cdot \frac{13}3=\frac{403}{27}</var>$

 

$<var>5)x.y/x+y=y+y=2y=2 \cdot \frac{31}9=\frac{62}9</var>$

 

$<var>6)x:y/x+y=\frac{x}{y} \cdot \frac1{x}+y=\frac1{y}+y=\frac9{31}+\frac{31}9=\frac{81+961}{279}=\frac{1042}{279}\\\\ 7)x.y/x:y=xy/x:y=y:y=1</var>$