Question

Fatore:
(x+y-z)³-(x-y+z)³ para x= -y = 1 e z = -2
Resposta :-8

Answer 1

$x=\frac{y}{2}=\frac{z}{3}=1\begin{cases} x=1\\y=2\\z=3\end{cases}$

Segue,

$(x+y-z)^3-(x-y+z)^3=\\(1+2-3)^3-(1-2+3)^3=\\0^0-(2)^3=\\0-8=\\\boxed{\boxed{-8}}$