Question

inequação 7(3x+2)>14-4(5x+3)

Answer 1

$7(3x+2)\ \textgreater \ 14-4(5x+3)\to \\\\ 21x+14\ \textgreater \ 14-20x-12\to \\\\ 21x+20x\ \textgreater \ 14-12-14\to \\\\ 41x\ \textgreater \ -12\to \\\\ x\ \textgreater \ - \frac{12}{41} \\\\\\ \boxed{S=\{xER|~x\ \textgreater \ - \frac{12}{41} \}}$

Answer 2

$7(3x+2) \ \textgreater \ 14-4(5x+3) \\\\ 21x+14 \ \textgreater \ 14-20x-12 \\\\ 21x+20x \ \textgreater \ 14-14-12 \\\\ 41x \ \textgreater \ -12 \\\\ \boxed{x \ \textgreater \ -\frac{12}{41}}$

Portanto a solução é:

$\boxed{\boxed{S = \{x \epsilon \mathbb{R} \ | \ x\ \textgreater \ -\frac{12}{41} \}}}$