Question

Me ajudem nessa por favor.

Answer 1

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2a} =\frac{-(-5)+\sqrt{(-5)^2-4.4.c} }{2.4} \\\\x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2a} =\frac{-(-5)-\sqrt{(-5)^2-4.4.c} }{2.4} \\\\x_1.x_2=-\frac{3}{2}\\\\\frac{-(-5)+\sqrt{(-5)^2-4.4.c} }{2.4}.\frac{-(-5)-\sqrt{(-5)^2-4.4.c} }{2.4}=-\frac{3}{2}$

$\frac{5+\sqrt{25-16.c} }{8}.\frac{5-\sqrt{25-16.c} }{8}=-\frac{3}{2}\\\\(5+\sqrt{25-16.c}).(5-\sqrt{25-16.c})=-\frac{3.64}{2}\\\\(5+\sqrt{25-16.c}).(5-\sqrt{25-16.c})=-96\\\\5^2-(25-16.c)=-96\\\\25-25+16.c=-96\\\\16.c=-96\\\\c=-6$