Question

se f (z)=z ao quadrado -z+1 então f (1-i) é igual a :

Answer 1

$f(z)=z^{2}-z+1\\\\f(z)=z(z-1)+1\\\\f(1-i)=(1-i)(1-i-1)+1\\\\f(1-i)=(1-i)\cdot(-i)+1\\\\f(1-i)=-i+i^{2}+1\\\\f(1-i)=-1-1+1\\\\\boxed{\boxed{f(1-i)=-i}}$